Skip to main content

Transformer Calculator

By · Updated Aug 2026

Calculate transformer kVA, primary and secondary line current, connection-aware winding ratio, or an infinite-source secondary fault-current screen from nameplate impedance.

kVA
A
kW
PF
Use measured, nameplate, or project load data when available. Power factor is required when the load is entered in kW.
V
V
For three-phase ratio calculations, choose the actual winding connection shown by the transformer configuration or nameplate.
For a 208Y/120 V secondary, choose Wye and enter 208 V as the line-to-line voltage.
turns
Share

How to Use

  1. Choose the transformer question - use rating mode for full-load currents, load mode for required kVA, or ratio mode for the ideal winding-voltage/turns relationship.
  2. Use line-to-line voltage for three-phase - enter the transformer nameplate line voltages. The calculator then converts those values to per-winding voltage from the selected Delta or Wye connection.
  3. Enter kW with power factor when that is your load data - load kW must be converted to apparent power before transformer sizing. Omitting PF can undersize the mathematical kVA requirement.
  4. Use %Z only when you have actual nameplate data - the optional fault-current result divides secondary full-load current by per-unit impedance and assumes an infinite primary source. It is not a complete short-circuit study.
  5. Check a candidate transformer if you have one - in load mode, the optional rating check compares the entered load and your planning target with an existing or proposed transformer kVA rating.
  6. Keep protection and conductor sizing separate - this page does not choose breakers, fuses, conductors, grounding, or equipment. Those remain separate design checks.

Quick answer

For a 75 kVA, 480 V Delta to 208Y three-phase transformer, line current is about 90.2 A on the primary and 208.2 A on the secondary. The line-voltage ratio is 2.3077:1, but the winding-voltage/turns ratio is about 3.997:1 because each Wye secondary winding sees 208/√3 ≈ 120 V. If the nameplate impedance is 5%, the infinite-source secondary fault-current screen is about 4.16 kA.

Line Values and Winding Values Are Not Always the Same

Delta primaryVwinding = VLLWye secondaryVwinding = VLL ÷ √3Turns ratio follows winding voltage, not blindly the two line-voltage numbers.
For three-phase transformers, line voltage can be enough for full-load current, but winding turns ratio depends on the actual Delta/Wye connections.

Transformer kVA and Full-Load Current

Transformer nameplates are commonly rated in kVA. Single-phase full-load current is kVA × 1000 ÷ volts. Balanced three-phase line current is kVA × 1000 ÷ (√3 × line-to-line volts). The same nameplate kVA therefore produces different primary and secondary line currents when the winding voltages differ.

Load mode reverses the relationship. If the secondary load is entered as amps, the calculator derives the minimum kVA from voltage, current, and phase. If the load is entered as real kW, it first divides kW by power factor to obtain apparent kVA. An optional user-selected margin can then be added to that mathematical minimum.

The margin is user-selected because there is no single percentage that fits every transformer application. Motors, nonlinear loads, medical equipment, duty, temperature, future load, voltage regulation, and manufacturer requirements can all change transformer selection.

For a long primary or secondary run, current alone is not the whole conductor check. After the operating current and conductor size are known, use the Voltage Drop Calculator to evaluate the run separately.

Example Transformer Full-Load Currents

TransformerPhasePrimary line currentSecondary line current
25 kVA · 240→120 VSingle-phase104.17 A208.33 A
45 kVA · 480→208 VThree-phase54.13 A124.90 A
75 kVA · 480→208 VThree-phase90.21 A208.18 A
112.5 kVA · 480→208 VThree-phase135.32 A312.27 A

Mathematical full-load currents only. Protection, conductor ampacity, inrush, harmonics, grounding, and product suitability are separate checks.

Worked Load-Sizing Example

StepExampleResult
Load60 kW at PF 0.8075.00 kVA mathematical load
Planning margin20% selected by the user90.00 kVA planning target
Candidate transformer112.5 kVA66.7% loaded by the entered load
Remaining capacity112.5 - 75.0 kVA37.50 kVA before considering other project limits

The candidate-rating check is arithmetic, not product approval. Starting current, harmonics, duty, temperature, voltage regulation, future load, protection, and manufacturer requirements can change the final selection.

Why Delta and Wye Matter for Turns Ratio

For an ideal single-phase transformer, Vp/Vs = Np/Ns. The same winding-voltage relationship applies to each phase of a three-phase transformer, but line voltage and winding voltage are not identical in every connection.

In a Delta winding, each winding is across the line-to-line voltage. In a Wye winding, each winding sees line-to-neutral voltage, which is line-to-line voltage divided by √3 in a balanced system. That means a 480Δ-to-208Y transformer has a line ratio of 480/208 ≈ 2.31, while the winding ratio is 480/(208/√3) ≈ 4.00.

The connection selectors are used only to explain winding voltage/current and turns ratio. They do not model vector-group phase displacement, grounding, taps, regulation, core design, saturation, or harmonics.

Optional Secondary Fault-Current Screen

When the transformer nameplate impedance is known, an initial maximum secondary fault-current screen can be made by dividing secondary full-load current by impedance expressed as a per-unit value. For 5% impedance, divide by 0.05.

This is the transformer-limited infinite-source case. Real available fault current also depends on the upstream source, feeder impedance, transformer tolerances, conductors, connections, and the location of the fault. Use it only as a screening number before a proper short-circuit study when equipment interrupting ratings are involved.

Do not guess transformer impedance. Use actual nameplate or manufacturer data for the specific unit.

Transformer Formulas Used

The calculator keeps line quantities and winding quantities separate:

Single-phase line current = I = kVA × 1000 ÷ V
Three-phase line current = I = kVA × 1000 ÷ (√3 × VLL)
Load amps to kVA, 1φ = kVA = V × I ÷ 1000
Load amps to kVA, 3φ = kVA = √3 × VLL × I ÷ 1000
Load kW to kVA = kVA = kW ÷ PF
Delta winding = Vphase = VLL; Iphase = Iline ÷ √3
Wye winding = Vphase = VLL ÷ √3; Iphase = Iline
Ideal winding turns ratio = Np ÷ Ns = Vphase,p ÷ Vphase,s
Infinite-source secondary fault current = Isc ≈ Isecondary,FL ÷ (%Z ÷ 100)

The equations are planning relationships, not a transformer design, protection study, or product selection.

Authoritative Technical Sources

Next Steps

After transformer current is known, continue with the checks that use that current:

  1. Size the primary or secondary conductorUse the applicable current plus installation conditions and voltage-drop needs.
  2. Review overcurrent protection separatelyTransformer protection has equipment-specific rules; use the breaker tool only as a general circuit-planning aid where its scope fits.

Related Calculators

Transformer calculations sit inside a larger electrical workflow. Browse the electrical calculator collection for load, current, conductor, protection, and raceway checks.

FAQ

Why does a 480 Delta to 208 Wye transformer not have a 2.31:1 winding turns ratio?
Because 480 V is across each Delta primary winding, while each Wye secondary winding sees about 120 V (208/√3). The line-voltage ratio is about 2.31:1, but the winding-voltage and ideal turns ratio is about 4.00:1.
Can I size a transformer from kW alone?
Not correctly when power factor is below 1. Apparent power is kVA = kW ÷ PF, so omitting PF can undersize the mathematical kVA requirement. Use actual load data and check special-load requirements.
Does the fault-current result replace a short-circuit study?
No. It is the transformer-limited infinite-source screen using nameplate impedance. Upstream source impedance and downstream conductor/system impedance can materially change available fault current at actual equipment.
Does this calculator size transformer breakers or conductors?
No. It returns transformer electrical relationships. Overcurrent protection, conductors, grounding, inrush, harmonics, local code, equipment listing, and manufacturer requirements are separate decisions.
Should I enter 208 V or 120 V for a 208Y/120 V secondary?
Enter 208 V as the three-phase line-to-line secondary voltage. If Wye is selected, the calculator derives approximately 120 V across each secondary winding internally.

Updated Aug 2026 · See our Methodology
Transformer planning calculator only. Full-load current and kVA relationships are mathematical. Connection-aware turns values are ideal winding relationships. The optional fault-current result assumes an infinite primary source and actual transformer nameplate impedance; it is not a complete short-circuit or coordination study. Verify transformer selection, protection, conductors, grounding, inrush, harmonics, temperature, duty, voltage regulation, and manufacturer/project requirements with qualified electrical professionals and the applicable code.